>> Do you flush the streams?
>>
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>
> Well, i tried flushing. It doesn't work.
When you say "It doesn't work", it's not clear to me what the problem
is. Exceptions being thrown? Application deadlocks? Characters arrive in
random order? etc.
> Since the "outer" inputstream gets what it needs, there shouldn't be a
> reason to flush the outputstreams... or should there?
Closing an output stream in itself should not "unblock" the input
stream, but usually when an output stream closes, it first flushes itself.
That is why I ask if you tried flushing.
> Reading and writing are in seperate threads, yeah. Each of the four
> streams are in their own thread.
This is strange to me. I expected for there to be two threads, not four.
One thread is producing data which is pushes into the FooOutputStream, which
then forwards the data to the PipedOutputStream (all within the same
thread). Then, a second thread, reads from the FooInputStream, which then
requests data from the PipedInputStream, and then consumes the data.
- Oliver
Carsten H. Pedersen - 14 Feb 2006 23:10 GMT
>> Well, i tried flushing. It doesn't work.
>
> When you say "It doesn't work", it's not clear to me what the problem
> is. Exceptions being thrown? Application deadlocks? Characters arrive in
> random order? etc.
Well, it does not change anything in what's going on. So a deadlock of
some sort i would guess. The characters arrive in the order they
should to the inner.
>> Reading and writing are in seperate threads, yeah. Each of the four
>> streams are in their own thread.
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> FooInputStream, which then requests data from the PipedInputStream, and
> then consumes the data.
Yeah... i tried to replicate my problem on a smaller scale. I'm
fiddling with RMI. So two clients, each of whom has the Foo* Streams,
and inside these there is a Remote interface, which can call read()
and write(), respectively, on an object on the server. This object
being a stream, which extends PipedOutputStream (or PipedInputStream),
and the two clients communicate with eachother with the server (and
the pipes) as a proxy.
So i just made it all local, and put them all in their seperate
threads to test it... but i still get the deadlock.
Same thing happens in the RMI scenario, though:
client1 -> client1outputstream.write -> serveroutputstream.write ->
serverinputstream.read -> client2inputstream.read -> deadlock (->
client2)
I would be happy to try another solution to exchange this data between
the clients, though. It's not a must to do it this way, it's just the
way that i just sorta stumbled upon. And since this error arose, and i
don't understand, i thought i'd at least attempt to solve it before
possibly moving on to another solution.
/Carsten
Oliver Wong - 15 Feb 2006 14:19 GMT
>> This is strange to me. I expected for there to be two threads, not
>> four. One thread is producing data which is pushes into the
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> which extends PipedOutputStream (or PipedInputStream), and the two clients
> communicate with eachother with the server (and the pipes) as a proxy.
How many threads does each client have, and what does each thread do?
- Oliver
Carsten H. Pedersen - 15 Feb 2006 15:48 GMT
>> Yeah... i tried to replicate my problem on a smaller scale. I'm
>> fiddling with RMI. So two clients, each of whom has the Foo* Streams,
[quoted text clipped - 7 lines]
>
> - Oliver
Each client only has one thread. Client A writes data to its
FooOutputStream, which writes to its associated PipedOutputStream on
the server. Client B reads data from its FooInputStream, which reads
from its associated PipedInputStream (which is connected to the
PipiedOutputStream associated with client A) on the server. It then
blocks before data is returned from FooInputStream to client B.
If i close the output stream it returns - which means that it's
closing the output stream on the server, since calling close on the
FooOutputStream just sends to the call to the PipedOutputStream on the
server.
/Carsten
Oliver Wong - 16 Feb 2006 14:30 GMT
>> How many threads does each client have, and what does each thread do?
>>
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> FooOutputStream just sends to the call to the PipedOutputStream on the
> server.
Okay, sorry, but I'm stumped then. =)
- Oliver
Carsten H. Pedersen - 17 Feb 2006 10:04 GMT
> Okay, sorry, but I'm stumped then. =)
>
> - Oliver
Thanks for trying, though. :) I think i'm missing something about how
streams behave. Since closing the outputstream seems to flush it, it's
gotta be close to working... maybe.
/Carsten
Godspeed - 01 Mar 2006 12:41 GMT
More code please.
>> Okay, sorry, but I'm stumped then. =)
>>
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>
> /Carsten