the second makes an extra copy of the string "java". The first points
to the interned copy possibly already extant. There is almost never a
need for the second form.

vahid.xplod@gmail.com wrote On 03/27/06 16:42,:

   The two samples above have identical effect: They
both cause the Java compiler to emit an error message
and reject the program ...

   I know you're trying to ask something, but I'm not
at all sure what it is you're asking.  This is only a
guess at what your question might be; if I've guessed
wrong, please try phrasing your question more precisely.

   Perhaps you are asking about

    String x = "java";
    String y = "java";
    String z = new String("java");

   The first line creates "by magic" a String whose
value consists of the four characters j a v a, and causes
the reference variable x to point to that String.  The
second line does the same, and in fact y will point to
the exact same String instance x does.  One String object,
two reference variables both pointing to it.  Clear so far?

   The third line gets hold of that same four-letter
String and passes it to a constructor as an argument.
The constructor does its duty, which is to create and
initialize a brand-new String object, and the reference
variable z is set to point to this new String.  This
particular constructor initializes its new String by
copying the contents of an existing String, so the new
String will also contain the four letters j a v a -- but
it is not the same String that x and y point to.  It is
a distinct String that just happens to have the same
content as the original.  (There are five pennies in my
pocket and five pennies in your pocket; the pockets'
contents are equal but the pockets are distinct.)

   You can demonstrate this odd state of affairs by
printing the results of a few simple tests:

    System.out.println(x.equals(y) + "\t" + (x == y));
    System.out.println(x.equals(z) + "\t" + (x == z));
    System.out.println(y.equals(z) + "\t" + (y == z));

Try to predict the output, then compile it and run it and
see whether you were right.

   ... and if that's not what you were asking about,
try asking again.

i my opinion.the 2nd String b=new String("hhhh"); made a copy of
"hhhh".
do this code
 String a="hhhh";
String b="hhhh";
String c=new("hhhh");

? a==b  .it will print true
but b==c,it will print false;

because a and b have the same Quote