String.Format()

Thread view:

Vespasian - 14 Nov 2005 06:13 GMT

why does System.out.println(String.format("%.20f", 1.0/3.0)); print

0.33333333333333330000

It should print out 20 3's. How can I fix this

TIA,
ves

Reply to this Message

Chris Smith - 14 Nov 2005 06:51 GMT

> why does System.out.println(String.format("%.20f", 1.0/3.0)); print
>
> 0.33333333333333330000
>
> It should print out 20 3's. How can I fix this

Floating point numbers have a fixed limited precision, and you're
surpassing it. If you need greater precision, take a look at the
BigDecimal class. Fortunately for you, String.format works just as
easily with BigDecimal as with normal floating point types.

Signature

www.designacourse.com
The Easiest Way To Train Anyone... Anywhere.

Chris Smith - Lead Software Developer/Technical Trainer
MindIQ Corporation

Reply to this Message

Fabien Bergeret - 14 Nov 2005 10:40 GMT

> why does System.out.println(String.format("%.20f", 1.0/3.0)); print
>
[quoted text clipped - 4 lines]
> TIA,
> ves

Floating point number are always an approximation of real numbers ...
and you've reched the limit of the approximation.

Maybe you should try to use BigDecimal

Reply to this Message

Free Magazines

Get these publications absolutely FREE for up to 12 months. There are no hidden fees and no obligation. Simply choose a title, complete the application form and submit it. Read more ...