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Java Forum / First Aid / December 2004Why is Double different from new Double()
I have a method that requires a Number as an argument If I do this Double x = new Double("2"); numberMethod(x); It doesn't compile with a not found error nor does numberMethod((Number)x); where as numberMethod(new Double(x)); does compile. Can any one explain it? Bob > I have a method that requires a Number as an argument > [quoted text clipped - 15 lines] > > Bob Could you display the error message?  Signature------------- - ByteCoder - ...I see stupid people ------------- Curiosity *Skilled* the cat Could you post the code and the error messages? >I have a method that requires a Number as an argument > [quoted text clipped - 4 lines] > > It doesn't compile with a not found error My guess is your "x" has gone out of scope, but as others have said, post some code. See: http://www.physci.org/codes/sscce.jsp > I have a method that requires a Number as an argument > [quoted text clipped - 15 lines] > > Bob Your problem description is incorrect. Please state is correctly. Also, state whether you are using a 1.5 or lower compiler. Here's some trivia for the curious: Does this compile on <=1.4 and/or 1.5? why (not)? double[] d = new double[0].clone(); SignatureTony Morris http://xdweb.net/~dibblego/ > Here's some trivia for the curious: > Does this compile on <=1.4 and/or 1.5? why (not)? > > double[] d = new double[0].clone(); Well, first I'm interested in why it compiles without a cast. Second, I know that some compilers used to think that cloning an array could throw a CloneNotSupportedException. Is that what you're referring to? Free MagazinesGet these publications absolutely FREE for up to 12 months. There are no hidden fees and no obligation. Simply choose a title, complete the application form and submit it. Read more ...
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