Hello everybody,
My application needs to keep reading files from the directory in which it
will be intsalled. How can I implement this in my code?
I don't think that something like System.getProperty("user.dir") is what I
am after, as the user may have a batch file and run the application from
wherever he/she likes. I don't want the directory the application is running
from currently, but the actual installation directory. (By the way, this
should also be cross platform ).
Any ideas?
Thank you in advance,
Sveta
Paul Lutus - 29 Aug 2004 23:37 GMT
> Hello everybody,
>
[quoted text clipped - 9 lines]
>
> Any ideas?
public class AppDirLocation {
static public void main(String[] args)
{
AppDirLocation app = new AppDirLocation();
System.out.println(app.getClass().getProtectionDomain()
.getCodeSource().getLocation());
}
}
This can be done statically as well:
(class name).getProtectionDomain().getCodeSource().getLocation()

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Paul Lutus
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Andrew Thompson - 30 Aug 2004 01:42 GMT
> I don't think that something like System.getProperty("user.dir") is what I
> am after,
..right idea, wrong user directory, put the files in "user.home"..
<http://www.physci.org/codes/javafaq.jsp#path>
HTH

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Andrew Thompson
http://www.PhySci.org/ Open-source software suite
http://www.PhySci.org/codes/ Web & IT Help
http://www.1point1C.org/ Science & Technology
Paul Lutus - 30 Aug 2004 02:53 GMT
>> I don't think that something like System.getProperty("user.dir") is what
>> I am after,
>
> ..right idea, wrong user directory, put the files in "user.home"..
> <http://www.physci.org/codes/javafaq.jsp#path>
The OP actually wants the directory the running application is located in. I
know this isn't always possibe, but see my other post for one answer.

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Paul Lutus
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Sveta - 30 Aug 2004 08:49 GMT
Many thanks,
would (class name).getProtectionDomain().getCodeSource().getLocation() work
for jar as well?
Sveta
Paul Lutus - 30 Aug 2004 09:01 GMT
> Many thanks,
>
> would (class name).getProtectionDomain().getCodeSource().getLocation()
> work for jar as well?
Why don't you try it? Don't you have access to a Java compiler? Create the
example program, run it, satisfy yourself that it works, then jar it and
try again.

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Paul Lutus
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Sveta - 30 Aug 2004 11:28 GMT
OK, will also do this later. In the meanwhile I tried:
System.out.println("Loaded MyInterface from:" +
MyInterface.class.getProtectionDomain().getCodeSource().getLocation());
and it keeps coming up with null pointer exception messages.
Also tried
this.getClass().etc
and also this.getClass().getResource("MyInterface.class") all come up with
problems : java.lang.NullPointerException
Sveta
Andrew Thompson - 30 Aug 2004 13:18 GMT
> and also this.getClass().getResource("MyInterface.class") all come up with
> problems : java.lang.NullPointerException
If MyInterface.class is in package mypackage,
you need to reference it as..
this.getClass().getResource("mypackage/MyInterface.class");
But.. whay are you not importing this class?
Why are you trying to load it by name?

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Andrew Thompson
http://www.PhySci.org/ Open-source software suite
http://www.PhySci.org/codes/ Web & IT Help
http://www.1point1C.org/ Science & Technology
Sveta - 30 Aug 2004 14:04 GMT
Paul/Andrew
thanks for the suggestions.
Actually, both these now work (haven't tried with jar yet):
ClassLoader.getSystemClassLoader().getSystemResource("MyInterface.class"));
and MyInterface.class.getProtectionDomain().getCodeSource().getLocation());
The probelm was possibly that the first time I run the application through
the GUI IDE which may have interferred?? (and yes the application was in a
package). Then I stopped using the IDE but in the meanwhile I managed to
insert a bug in the init() method !
(Sorry for the extra message due to my fault...)
The whole point of doing this was to be able to dynamically get the names of
the files from which info is read.
I have a version using an environmental variable but I preferred not to have
to set anything and make the program able to sort things out by itself.
And I had no clue how to do this (importing? not sure how).
Sveta
> > and also this.getClass().getResource("MyInterface.class") all come up with
> > problems : java.lang.NullPointerException
[quoted text clipped - 6 lines]
>
> Why are you trying to load it by name?
Paul Lutus - 30 Aug 2004 16:55 GMT
> OK, will also do this later. In the meanwhile I tried:
>
> System.out.println("Loaded MyInterface from:" +
> MyInterface.class.getProtectionDomain().getCodeSource().getLocation());
>
> and it keeps coming up with null pointer exception messages.
In order to get assistance, you must post a short, complete, compilable
example of the problem code.

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Paul Lutus
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