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Java Forum / General / October 2007Jar
Hello all, I know this can be done, I know it is simple, but I cant find the methods. I would like to extract a file included in the jar file of my application. I would like to get it as a byte[]. Can you tell me how to do that? Also could you give me a path to the classes and methods dealing with resources in jar files? Thanks in advance Ouabaine, 15.10.2007 16:32: > Hello all, > [quoted text clipped - 4 lines] > you give me a path to the classes and methods dealing with resources in jar > files? Classloader.getResourceAsStream() or Class.getResourceAsStream() both return an InputStream which you can use to read the file. The first one allows you to specify the location inside the jar file, the second one assumes the "resource" file is located in the same package (i.e. directory) where the .class file is located. Thomas > Classloader.getResourceAsStream() or Class.getResourceAsStream() both > return an InputStream which you can use to read the file. > > The first one allows you to specify the location inside the jar file, > the second one assumes the "resource" file is located in the same > package (i.e. directory) where the .class file is located. Not true. The two are exactly equivalent, in fact, the Class version invokes the ClassLoader version. <http://java.sun.com/javase/6/docs/api/java/lang/Class.html#getResourceAsStream(j ava.lang.String)> > This method delegates to this object's class loader.  SignatureLew > > Classloader.getResourceAsStream() or Class.getResourceAsStream() both > > return an InputStream which you can use to read the file. [quoted text clipped - 9 lines] > > > This method delegates to this object's class loader. And, if you read the remaining of the documentation, you'll find this: Before delegation, an absolute resource name is constructed from the given resource name using this algorithm: * If the name begins with a '/' ('\u002f'), then the absolute name of the resource is the portion of the name following the '/'. * Otherwise, the absolute name is of the following form: modified_package_name/name Where the modified_package_name is the package name of this object with '/' substituted for '.' ('\u002e'). This means that if the file is stored in the same package/directory as the class, you mya just use MyClass.class.getResourceAsStream("myFile.txt"). JB. > And, if you read the remaining of the documentation, you'll find this: > [quoted text clipped - 12 lines] > the class, you mya just use > MyClass.class.getResourceAsStream("myFile.txt"). Wouldn't getClass().getClassLoader().getResourceAsStream("myFile.txt") return the same resource? SignatureLew > > This means that if the file is stored in the same package/directory as > > the class, you mya just use > > MyClass.class.getResourceAsStream("myFile.txt"). > > Wouldn't getClass().getClassLoader().getResourceAsStream("myFile.txt") return > the same resource? No. It would return null. The above code would only load myFile.txt if myFile.txt is at the root (in the default package). JB. > -- > Lew >>> This means that if the file is stored in the same package/directory as >>> the class, you mya just use [quoted text clipped - 4 lines] > No. It would return null. The above code would only load myFile.txt if > myFile.txt is at the root (in the default package). Thank you. I have new understanding. SignatureLew > Classloader.getResourceAsStream() or Class.getResourceAsStream() both > return an InputStream which you can use to read the file. > > The first one allows you to specify the location inside the jar file, > the second one assumes the "resource" file is located in the same > package (i.e. directory) where the .class file is located. I had to read this whole thread like four times before I finally got exactly what was being said here. That *is* an evil collision of method names here. Seems to me that Sun should deprecate the first and provide a non-deprecated version named Classloader.getResourcePathAsStream() or something... >I would like to extract a file included in the jar file of my application. I >would like to get it as a byte[]. Can you tell me how to do that? Also could >you give me a path to the classes and methods dealing with resources in jar >files? a Jar is also a Zip file. See http://mindprod.com/jgloss/zip.html for simple unpacking. a SignatureRoedy Green Canadian Mind Products The Java Glossary http://mindprod.com > Hello all, > [quoted text clipped - 4 lines] > you give me a path to the classes and methods dealing with resources in jar > files? To summarize the two above threads, use getResource() and friends if you are loading a file from your own currently executing jar: http://java.sun.com/j2se/1.4.2/docs/api/java/lang/ClassLoader.html If you are manipulating a separate jar file (perhaps adding a special config file, or modifying the manifest file) use java.util.jar http://java.sun.com/j2se/1.4.2/docs/api/java/util/jar/package-summary.html Free MagazinesGet these publications absolutely FREE for up to 12 months. There are no hidden fees and no obligation. Simply choose a title, complete the application form and submit it. Read more ...
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