Basically, the calculation without log is -

x / [ 1-1/(1+x)^n]

So, when you take log, you get logx - log(1-(1/(1+x)^n))

But, when I'm doing this same in Java, I'm getting this error
"Operator ^ cannot be applied to double.." How come  o.0

public static double f(double x) {

       return Math.log(x)-Math.log(1-(1/(1+x)^n));

   }