If there is a new line in the input String, it's easy.  There are several
methods in the String class that can detect where the '\n' is; see the Javadocs.

If there is no new line in the input you're SOL.

I'm not the expert at all, but I think this will work.  Make a Reader
object from the String:

String willie = "To be or not to be, that is the question.\nWilliam
Shakespear"
StringReader willieReader = new StringReader( willie );

Then use that to make a BufferedReader, which has a readLine method.

BufferedReader bufferedWillieReader = new BufferedReader( willieReader );

String line = bufferedWillieReader.readLine();

I'm sure there's a way to do this just with String methods, but this
might be the most general, since the BufferReader will also let you read
from files.  I found this just by poking around the only Java API that
Sun maintains:

http://java.sun.com/j2se/1.3/docs/api/java/io/BufferedReader.html

If there is a \n at the split, use indexOf('\n');
if there in a \r\n at the spit, us indexOf("\r\n");
If the . is the only indication, indexOf again.
You can also use Regex.split see http://mindprod.com/jgloss/regex.html

Convert your String to char[] and have a look at what you have to work
with.

see http://mindprod.com/jgloss/conversion.html
--
Roedy Green Canadian Mind Products
The Java Glossary
http://mindprod.com