 |
 | Home | Contact Us | FAQ | Search & Site Map | Link to Us |
 | Sign In | Join | Other 45 Sites in Network |
Java Forum / General / May 2007do something every 1000 records or so
Ok, this could be a perfect exam question, but it isn't and i need a good solution in a function i get 2 int parameters : begin end they represent the number of records affected , I have to print to a log at the start of this and then every 1000 records or so, the code looks something like this: public Vector findRecords(int beginRange, int endRange) throws UierException { if beginRange == 0 || "some condition so it prints every 1000 records" { logIt(" Range affected" + beginRange + " to " + endRange); ..... I would really appreciate the help oh and by the way, the range varies, it could be 20, 40, 120, or whatever, so the condition has to check that between beginRange and endRange is more that 1000x i m not sure I m explaining the problem properly, so if its not clear please ask. also there might be an incredibly easy solution, but i just cant see it :( Thanks in advance for the help jo > Ok, this could be a perfect exam question, but it isn't and i need a > good solution I'll believe you. > if beginRange == 0 || "some condition so it prints every 1000 records" { I think you need the modulo (%) operator. This gives the remainder of an integer division, which will, of course be zero every n records when you modulo by n. For example 25 % 25 == 0, 50 % 25 == 0, 51 % 25 == 1 and so on.  SignatureRegards, Richard On May 15, 10:36 am, Richard Senior <nos...@r-senior.demon.co.uk> wrote: > > Ok, this could be a perfect exam question, but it isn't and i need a > > good solution [quoted text clipped - 11 lines] > > Richard hi there: the problem is that i dont have an exact brake, ie if i do a module on 1050 i ll get 1, and some mod but what happens when i get 1090? i ll get 1 again, so how do i make it print only the first time ? > the problem is that i dont have an exact brake, ie if i do a module on > 1050 i ll get 1, and some mod > but what happens when i get 1090? i ll get 1 again, so how do i make > it print only the first time ? I don't understand. Isn't this essentially what you want? public class Modulo { private static final int START = 1; private static final int FINISH = 50; private static final int INTERVAL = 5; public static void main(String[] args) { for (int i = START; i <= FINISH; i++) { if (i == START || i % INTERVAL == 0) { System.out.print(i); } else { System.out.print("."); } } } } SignatureRegards, Richard Thanks for your reply but no, have a look at the original code on the fucntion, that function is called for example with parameters findRecords(0,39) findRecords(40,120) findRecords(121,200) .... or findRecords(0, 60) findRecords(61, 120) findRecords(121, 180) ... what i need to implement is that if between beginRange and endRange there is a 000 number then i run the line logIt(" Range affected" + beginRange + " to " + endRange); Where logit is a custom function that writes to a log in my app. I hope is a bit more clear now Thanks jo On May 15, 2:33 pm, Richard Senior <nos...@r-senior.demon.co.uk> wrote: > > the problem is that i dont have an exact brake, ie if i do a module on > > 1050 i ll get 1, and some mod [quoted text clipped - 28 lines] > > Richard > Thanks for your reply but no, > have a look at the original code on the fucntion, that function is > called for example with parameters > > findRecords(40,120) Within this call to findRecords(), is there a loop that looks at record 40, 41, 42, 43 ... and so on, up to 120? > what i need to implement is that if between beginRange and endRange > there is a 000 number then i run the line > > logIt(" Range affected" + beginRange + " to " + endRange); > > Where logit is a custom function that writes to a log in my app. And do you want to call your logIt() function when you have found or processed 1000 records, 2000 records, etc.? SignatureRegards, Richard On May 15, 4:53 pm, Richard Senior <nos...@r-senior.demon.co.uk> wrote: > > Thanks for your reply but no, > > have a look at the original code on the fucntion, that function is [quoted text clipped - 4 lines] > Within this call to findRecords(), is there a loop that looks at record > 40, 41, 42, 43 ... and so on, up to 120? No, this queries a db in that range > > what i need to implement is that if between beginRange and endRange > > there is a 000 number then i run the line [quoted text clipped - 5 lines] > And do you want to call your logIt() function when you have found or > processed 1000 records, 2000 records, etc.? yes, exactly > -- > Regards, > > Richard >> And do you want to call your logIt() function when you have found or >> processed 1000 records, 2000 records, etc.? > > yes, exactly So, make a loop with a counter and use the modulo operator like I showed you. I'm not going to write it for you. SignatureRegards, Richard > findRecords(0,39) > findRecords(40,120) [quoted text clipped - 8 lines] > what i need to implement is that if between beginRange and endRange > there is a 000 number then i run the line private int LOGEVERY = 1000; ... if ((beginRange == 0) || (endRange / LOGEVERY) > (beginRange / LOGEVERY)) logIt ("Range affected" + beginRange + " to " + endRange); > > findRecords(0,39) > > findRecords(40,120) [quoted text clipped - 15 lines] > (endRange / LOGEVERY) > (beginRange / LOGEVERY)) > logIt ("Range affected" + beginRange + " to " + endRange); hey Z, yes thats nearly there, actually ((startRange/1000) != (endRange/1000)) is what worked but thatnks a million for your help Jo Free MagazinesGet these publications absolutely FREE for up to 12 months. There are no hidden fees and no obligation. Simply choose a title, complete the application form and submit it. Read more ...
|
Reply to this Message
|
 Sign In
 Join
 My Latest Posts My Monitored Threads My Blog My Photo Gallery My Profile My Homepage Start New Thread Enable EMail Alerts Rate this Thread
|
©2009 Advenet LLC Privacy Policy - Terms of Use
This website includes both content owned or controlled by Advenet as well as content owned or controlled by third parties.