Initializing final variables

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Christoph Burschka - 10 May 2007 08:37 GMT

I'm declaring a constant object in my class definition, whose
constructor throws an exception. Note that the exception never actually
gets thrown - my argument ensures that.

Apparently, I can't use try-catch blocks outside a method, so I can't
initialize this value in the class declaration. But if I don't
initialize it there, I can't declare it final.

Does this just mean I can't initialize final variables with
exception-throwing constructors, or is there a solution?

--cb

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Tom Hawtin - 10 May 2007 09:00 GMT

> I'm declaring a constant object in my class definition, whose
> constructor throws an exception. Note that the exception never actually
[quoted text clipped - 3 lines]
> initialize this value in the class declaration. But if I don't
> initialize it there, I can't declare it final.

private static final MyClass thing;
static {
try {
thing = new MyClass();
} catch (SomeException exc) {
throw new Error();
}
}

or

private static final MyClass thing = makeThing();
private static MyClass MakeThing() {
try {
return new MyClass();
} catch (SomeException exc) {
throw new Error();
}
}

Tom Hawtin

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