class VeryVerySimpleExample {
   public static void printArgs(String...args) {
       String[] array = args;
       System.out.println(array.length + " " + args.length);
       for (int i = 0; i < args.length; ++i) {
           System.out.println(args[i]);
      }
   }

  public static void main(String[]args) {
     printArgs();
     printArgs("Hello");
     printArgs("Hello", "World");
     printArgs(args);
     printArgs(new String[] {"This", "is", "not", "a", "drill"});
  }
}

So, hopefully my example shows you that:
A vararg is simple syntactic sugar for an array.
The Java compiler will automatically create a new array if one isn't
passed in.
There are a few other details to know about, but thats the basis of
it.

Hope this helps,
Daniel.