Hi,

I am new to java and I have troubles with doubles. I have 8 bytes and
I need to convert them to a single double. I searched the net and
found out this piece of code
(with all respect to the Author and his rights)

<code>
public static double arr2double(byte[] arr, int start) {
       int i = 0;
       int len = 8;
       int cnt = 0;
       byte[] tmp = new byte[len];
       for (i = start; i < (start + len); i++) {
           tmp[cnt] = arr[i];
           //System.out.println(java.lang.Byte.toString(arr[i]) + " "
+ i);
           cnt++;
       }
       long accum = 0;
       i = 0;
       for ( int shiftBy = 0; shiftBy < 64; shiftBy += 8 ) {
           accum |= ( (long)( tmp[i] & 0xff ) ) << shiftBy;
           i++;
       }
</code>

but when I gave the following array
<code>
   byte[] byteArray = new byte[]{0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0,
0x1};
</code>

instead of returning the value 1 (one) the above method returned me
some other
value. I even tried going through IEEE 754 standards but they were
absolutely
out of my scope.

Can any one guide me in "How to convert the given byte array into a
double value" ?

Thanks in advance for all Ur efforts
-F