I'd split the string on whitespace (to get {This, is, "very", 'tricky'.,
I, won't, be, able, see, it.}) and then write a function which acts like
trim(), but rather than removing leading or trailing whitespace, it removes
leading or trailing punctuation. That'll give {This, is, very, tricky, I,
won't, be, able, see, it} which you can then walk through and eliminate all
2 char characters or less.

   - Oliver

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Test {
   public static void main(String[] args) {
       Pattern longword = Pattern.compile("\\w+('?\\w){2,}");
       String input = "This is \"very\" 'tricky'. I won't be able see
it.";
       Matcher matcher = longword.matcher(input);
       while (matcher.find()) {
           System.out.println(matcher.group());
       }
   }
}