reading a file as an xsl instruction?

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Dhurandhar - 01 Nov 2006 05:34 GMT

How can I read a file as a template instruction in an xsl?

Upon matching a template, I need to add the contents of
an entire file in the result tree.

Is that possible?

(sorry if I am a bit fuzzy).

Regards,
D

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Manish Pandit - 01 Nov 2006 06:49 GMT

> (sorry if I am a bit fuzzy).

Yeah, it is kind of fuzzy. Are you trying to use XSLT and transform an
XML document with the XSL ? You can take a look at cocoon/xalan-j XSLT
processor for more info on how to do that.

-cheers,
Manish

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Mike Schilling - 01 Nov 2006 07:09 GMT

> How can I read a file as a template instruction in an xsl?
>
[quoted text clipped - 4 lines]
>
> (sorry if I am a bit fuzzy).

1. Write a custom XPath function, or
2. Pass the contents of the file in as the value of an XSLT parameter.

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Tor Iver Wilhelmsen - 01 Nov 2006 19:52 GMT

> Upon matching a template, I need to add the contents of
> an entire file in the result tree.

At the top:

<!DOCTYPE stylesheet (etc.) [
<!ENTITY includefile SYSTEM "thefile.xml">
]>

Then, in the template rule:

<xsl:template match="foo">
&includefile;
</xsl:template>

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Dhurandhar - 02 Nov 2006 01:20 GMT

> > Upon matching a template, I need to add the contents of
> > an entire file in the result tree.
[quoted text clipped - 10 lines]
> &includefile;
> </xsl:template>

That worked, but partially (thanks).
I am finding that in the resulting document, some of the characters are
stripped off. Thus, if
thefile.xml contains something like ${a.b.c}/d/e, the resulting
document only has $/d/e.

Am I missing something?

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reading a file as an xsl instruction?

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