One wrinkle is that Math.floor( x + 0.5 ) (not math.floor()) and Math.round()
will not perform standard IEEE rounding.  The standard specifies the behavior
of Math.rint() - "If two double values that are mathematical integers are
equally close, the result is the integer value that is even."

In other words, if a double value x were exactly equal to 6.5, then
Math.rint(x) would return 6.0, but Math.round(x) would return 7L.

- Lew

How's this?

import java.util.Scanner;
import java.util.*;

public class RoundFinder
{
 public void determineRound()
 {
    Scanner input = new Scanner( System.in );

    System.out.print("Enter three values separated by spaces: ");
    double number1 = input.nextDouble();
    double number2 = input.nextDouble();
    double number3 = input.nextDouble();

    double result = round( number1, number2, number3 );
    System.out.printf("(number1)= %f\n" , number1 );
    System.out.printf("(number2)= %f\n" , number2 );
    System.out.printf("(number3)= %f\n" , number3 );

    System.out.println( "Rounded Value is : " + result);

 }

public double round ( double x, double y, double z)

{
 double roundValue = Math.floor(x + 0.5);

 if ( y > roundValue )
     roundValue = y;

 if ( z > roundValue )
     roundValue = z;

 return roundValue;
}
}

OUTPUT:

Enter three values separated by spaces: 33.6
33.8
22.9
(number1)= 33.600000
(number2)= 33.800000
(number3)= 22.900000
Rounded Value is : 34.0