regex - extract before span

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skajotde@gmail.com - 14 Jul 2006 12:37 GMT

Hi all

I'd like extraxt before span.

example:

ff ff

to:

ff ff

* br outside of span

Pattern spanBR =
Pattern.compile("(<span[^>]*?>).*?(</span){0}.*?(<newline/>).*?(<span){0}.*?()",
Pattern.DOTALL | Pattern.CASE_INSENSITIVE);

Matcher matcherSpanBR = spanBR.matcher(html);

while (matcherSpanBR.matches()) {
html = matcherSpanBR.replaceAll("$1$2$5$1$3$1$4$5");
}

My question is how say "part of text without between and save this part text to register" (<newline/> is my br
aftter first conversion).

Cheers
Kamil

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skajotde@gmail.com - 14 Jul 2006 12:46 GMT

> Pattern spanBR =
> Pattern.compile("(<span[^>]*?>).*?(</span){0}.*?(<newline/>).*?(<span){0}.*?()",
> Pattern.DOTALL | Pattern.CASE_INSENSITIVE);

Before My pattenr looks like:

"(<span[^>]*?>)(.*?)(<newline/>)(.*?)()"

But this pattern matches:


 ff ff * Some
test: Some test

i have to move up recursive inside all span, any suggestions?

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Oliver Wong - 14 Jul 2006 15:11 GMT

>> Pattern spanBR =
>> Pattern.compile("(<span[^>]*?>).*?(</span){0}.*?(<newline/>).*?(<span){0}.*?()",
[quoted text clipped - 12 lines]
>
> i have to move up recursive inside all span, any suggestions?

Give up with regular expressions, and use a context free grammar based
parser instead. See http://java-source.net/open-source/html-parsers

- Oliver

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skajotde - 16 Jul 2006 10:57 GMT

> Give up with regular expressions, and use a context free grammar based
> parser instead. See http://java-source.net/open-source/html-parsers
>
> - Oliver

Yes, it's not too bad solution. At the moment i'm using this code:

// wylapanie 
Pattern badBR = Pattern.compile("<br.*?>", Pattern.DOTALL |
Pattern.CASE_INSENSITIVE);
Matcher matcherBR = badBR.matcher(html);
html = matcherBR.replaceAll("<newline/>");

// usuniecie pustych span'ow
Pattern emptySpan = Pattern.compile("<span[^>]*?>",
Pattern.DOTALL | Pattern.CASE_INSENSITIVE);
Matcher matcherSpan = emptySpan.matcher(html);
html = matcherSpan.replaceAll("");

// przesuniecie <newline/> ze spanu miedzy dwa spany
Pattern spanBR = Pattern.compile(

"(<span[^>]*?>)([^<>]*?)(<newline/>)([^<>]*?)()",
Pattern.DOTALL | Pattern.CASE_INSENSITIVE);
Matcher matcherSpanBR = spanBR.matcher(html);
int numLoop = 0;
while (matcherSpanBR.find() == true) {
html = matcherSpanBR.replaceAll("$1$2$5$3$1$4$5");
matcherSpan.reset(html);
// jeszcze raz usun puste span'y
html = matcherSpan.replaceAll("");
matcherSpanBR.reset(html);
numLoop++;
// max 3 poziomy zagniezdzenia
if (numLoop > 3) break;
}

I hope it's sufficient (my bug was resolved).

Thanks for help

Cheers
Kamil

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regex - extract <br> before span

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