hai members
this is my first topic ..
iam getting the problem while executing the below program
The exeception it is throwing is ...
////////////////////////////////////
please help me regarding this issue.
////////////////////////////////////
Exception in thread "main" java.net.UnknownHostException:
www.hotmail.com
at java.net.PlainSocketImpl.connect(Unknown Source)
at java.net.Socket.connect(Unknown Source)
at java.net.Socket.connect(Unknown Source)
at sun.net.NetworkClient.doConnect(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.<init>(Unknown Source)
at sun.net.www.http.HttpClient.<init>(Unknown Source)
at sun.net.www.http.HttpClient.New(Unknown Source)
at sun.net.www.http.HttpClient.New(Unknown Source)
at sun.net.www.http.HttpClient.New(Unknown Source)
at
sun.net.www.protocol.http.HttpURLConnection.plainConnect(Unknown Sour
ce)
at sun.net.www.protocol.http.HttpURLConnection.connect(Unknown
Source)
at
sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown So
urce)
at java.net.URL.openStream(Unknown Source)
at hostname.main(hostname.java:6)
///////////////////////////////////
My program
//////////////////////////////////
import java.net.*;
import java.io.*;
public class hostname {
public static void main(String argv[]) throws Exception {
URL url = new URL("http://www.hotmail.com");
BufferedReader in = new BufferedReader(new InputStreamReader(
url.openStream()));
String line;
StringBuffer sb = new StringBuffer();
while ((line = in.readLine()) != null) {
sb.append(line);
}
in.close();
System.out.println(sb.toString());
}
}
///////////////////////////
Gordon Beaton - 17 May 2006 14:21 GMT
> Exception in thread "main" java.net.UnknownHostException:
> www.hotmail.com
Are you behind a firewall?
Instead of
url.openStream()
try
url.openConnection(proxy).getInputStream()
/gordon

Signature
[ do not email me copies of your followups ]
g o r d o n + n e w s @ b a l d e r 1 3 . s e