You could add 1000*60*60*24 milliseconds to the date (see
java.util.GregorianCalendar) and check whether the month value has
changed after that.

Jeroen

Assuming you're using a western calendar, the exact length of the months is
very well known: April, June, September and November always have 30 days;
February has 28 days except when it is a leap year, in which case it has 29
days; all the remaining months always have 31 days. You can easily write a
method to determine if a given date goes beyond the end of a month; I've
done it in 4 or 5 languages over the years, including Java.

Remember, the rule for leap years is that is the year is a multiple of 100,
e.g. 1700, 1800, 1900, 2000, the year is only a leap year if the entire year
is evenly divisible by 400. Therefore, 1700, 1800, and 1900 are NOT leap
years but 2000 IS a leap year. If the year is NOT a multiple of 100, e.g.
2004, it IS a leap year if it is evenly divisible by 4.

--
Rhino

I would wrap a GregorianCalendar in my own utility class and have methods
that determine that by setting the calendar to the correct month:

private GregorianCalendar calendar = new GregorianCalendar();
// or instantiate with locale/timezone specifing version

public int getMaxDayInMonthofDate(Date myDate) {

   synchronized (calendar) {
       calendar.setTime(myDate); // instance of Date
       int maxDayInMyDatesMonth = calendar.getActualMaximum();
   }
   return maxDayInMyDatesMonth;
}

--
Mike W

On 6 May 2006 03:14:30 -0700, "rsujatha@gmail.com"
<rsujatha@gmail.com> wrote, quoted or indirectly quoted someone who
said :

The direct way is to use two tables of month lengths selected by
isLeap( yyyy ). and compare dd with that entry.

With BigDate you could use  d.addDays(1) then check if d.getMM() == 1.

see http://mindprod.com/jgloss/bigdate.html