Learning J2ee, got newbie question.

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DaLoverhino - 21 Feb 2006 23:17 GMT

Hello. I picked up a Beginner's J2ee book. I'm going through the
examples, but one of the examples I am stuck on. I cannot get past the
error message:

404 - Resource Not found.

I am running Tomcat, I believe 5.5.8. Here's the directory structure
that I have:

webapp/Ch05/
login.html
Login.java
Login.class

Here's the login.html:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Login</title>
</head>

<body>
<h1>Login</h1>

Please enter your username and password.
<form action="/Ch05/Login" method="POST">
<p><input type="text" name="username" length="40">
<p><input type="password" name="password" length="40">
<p><input type="submit" value="Submit">
</form>
</body>
</html>

My browser complains that Login resource is unavailable. Here's
Login.java, which is compiled and in the same directory.

package web;

import java.servlet.http.*;
import java.io.*;

public class Login extends HttpServlet {
public void doPost( HttpServletRequest request, HttpServletResponse
response)
{
String username = request.getParameter( "username");
try {
response.setContentType( "text/html");
PrintWriter writer = response.getWriter();
writer.println( "<html><body>");
writer,println( "Thank you, " + username +
". You are now logged into the system.");
writer.println( "</body></html>");
writer.close();
} catch( Exception e) {
e.printStackTrace();
}
}
}

Anyways, does anyone know what I'm doing wrong here? (I just typed the
example pretty quickly, so there might be typos, but the above compiles
without complaint.) Thanks.

Reply to this Message

info@hmdproducts.com - 22 Feb 2006 00:02 GMT

> Hello. I picked up a Beginner's J2ee book. I'm going through the
> examples, but one of the examples I am stuck on. I cannot get past the
> error message:
>
> 404 - Resource Not found.

Hope I didn't miss a detail. Check that the servlet is mapped
correctly in the web.xml file in the WEB-INF directory. It might need
something like:

<servlet-mapping>
<servlet-name>Login</servlet-name>
<url-pattern>/Ch05/Login</url-pattern>
</servlet-mapping>

HTH

-- Kyle

Reply to this Message

trippy - 22 Feb 2006 03:39 GMT

In article <1140563842.198568.224460@g43g2000cwa.googlegroups.com>,
DaLoverhino took the hamburger, threw it on the grill, and I said "Oh
wow"...

> Hello. I picked up a Beginner's J2ee book. I'm going through the
> examples, but one of the examples I am stuck on. I cannot get past the
[quoted text clipped - 36 lines]
>
> import java.servlet.http.*; //wrong

import javax.servlet.*;
import javax.servlet.http.*;

> import java.io.*;
>
[quoted text clipped - 20 lines]
> example pretty quickly, so there might be typos, but the above compiles
> without complaint.) Thanks.

Signature

trippy
mhm31x9 Smeeter#29 WSD#30
sTaRShInE_mOOnBeAm aT HoTmAil dOt CoM

NP: "I Am The Law" -- Anthrax

"Now, technology's getting better all the time and that's fine,
but most of the time all you need is a stick of gum, a pocketknife,
and a smile."

-- Robert Redford "Spy Game"

Reply to this Message

Paul Hamaker - 22 Feb 2006 08:38 GMT

Are you sure about the presence of Login.class where you suppose it to
be, because your source contains an error :
writer,println( "Thank you, " + us......
comma instead of dot

--------------------
Paul Hamaker, SEMM, teaching ICT since 1987
http://javalessons.com

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Learning J2ee, got newbie question.

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