Given the following XML file:

<?xml version='1.0' encoding='utf-8'?>
<!DOCTYPE hibernate-configuration SYSTEM
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
    <!-- a SessionFactory instance listed as /jndi/name -->
    <session-factory name="MySessionFactory">
    <property name="connection.url">jdbc:postgresql:test</property>
    <property name="connection.username">test</property>
    <property name="connection.password">test</property>
    </session-factory>
</hibernate-configuration>

I can't seem to figure out how to parse out the connection.url value of
"jdbc:postgresql:test".  Below is my code:

Document hibernateDoc = ParserAdapter.parseXmlFile(inputStream, false);
//
// Get a list of "property" elements
//
NodeList nodeList = hibernateDoc.getElementsByTagName("property");
for (int i=0; i<nodeList.getLength(); i++) {
  Node node = nodeList.item(i);
  //
  // Verify that the property is of "session-factory"
  //
  if (0 ==
node.getParentNode().getNodeName().compareToIgnoreCase("session-factory")) {
    Node attribute = node.getAttributes().getNamedItem("name");
    if ( null != attribute) {
      if (0 ==
attribute.getNodeValue().compareToIgnoreCase("connection.url")) {
        //
        // What now?
        //
      } else if (0 ==
attribute.getNodeValue().compareToIgnoreCase("connection.username")) {
      } else if (0 ==
attribute.getNodeValue().compareToIgnoreCase("connection.password")) {
      }
    }
  }
}