Implement serializable if I already extend it?

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timasmith@hotmail.com - 12 Dec 2005 03:27 GMT

If I extend an exception (which can be serialized) do I need to
explicitly implement serializable?

public class MyException extends Exception {

    static final long serialVersionUID = 1L;

    public MyException(Exception exception){
        super(exception);
    }

}

thank

Tim

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zero - 12 Dec 2005 03:30 GMT

timasmith@hotmail.com wrote in news:1134358077.170997.109570
@f14g2000cwb.googlegroups.com:

> If I extend an exception (which can be serialized) do I need to
> explicitly implement serializable?
[quoted text clipped - 12 lines]
>
> Tim

No.

The main reason for mentioning it, even though it's not really necessary,
would be to make it more obvious that you're implementing it. So it's
mostly for readability.

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Roedy Green - 12 Dec 2005 04:00 GMT

>If I extend an exception (which can be serialized) do I need to
>explicitly implement serializable?
[quoted text clipped - 6 lines]
> super(exception);
> }

Any subclass automatically implements all the interfaces of the base
class. You can optionally provide another serialVersionUID which can
be considered the version number of the extension fields
.

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Canadian Mind Products, Roedy Green.
http://mindprod.com Java custom programming, consulting and coaching.

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Implement serializable if I already extend it?

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