Hello Friends,

I am at a point where I need to understand how does the native jvm
function "do_execute_java_method_vararg", gets hold of the method
args. Thank you all, for reading through my post and please, if you
have any ideas that could help me learn this, please post them. I
would be very thankful.

The signature of the function 'do_execute_java_method_vararg" looks
like this:

long do_execute_java_method_vararg (ExecEnv * ee, void * obj,char *
method_name, char * method_signature,struct methodblock * mb, bool_t
isStaticCall,va_list args,long * otherBits, bool_t shortFloats)

As I understand that, the "args" in the signature should contain the
actual arguments that a method specified in the methodblock (mb,
above) takes.

So, how is this list traversed? So, if this is being traversed in the
way of a typical va_list, like:

va_start(args,ee->current_frame->optop); // Is the second parameter
correct here?

for(int i = 1 ; i < methodblockPtr->args_size; i++ )
{
if(shortFloats != 0)
{
longArg = va_arg( args,long );
//do something with this longArg
}
else
{
doubleArg = va_arg( args,double );
//do something with doubleArg
}

}//end for loop
va_end( args );

My question to you all, is that in "va_start", are the parameters that
I am assuming, Correct? I am very hopeful from you all, that I would
get help here, definitely. Thank you so much in advance.

Regards.