See the javadocs for the javax.swing.InputVerifier class.

   - Oliver

I did it with AWT classes, so surely you can do it with Swing.  It is
just a matter of how much code you are willing to write.

see http://mindprod.com/jgloss/validation.html

rspu...@yahoo.com wrote:

I'm not sure exactly what you mean by "etc." here but, depending on
how how many digits might be allowed, regular expressions might do
the trick.

My best guess is that you want to force the input string to be between
one and eight digits long. (The ninth char couldn't really be in the
[0-10] range, since 10 doesn't fit in a char.)

In this case you could do the following. It's ugly but it works.

java.util.regex.Pattern pat = java.util.regex.Pattern.compile(
 "[0-2]([0-3]([0-4]([0-5]([0-6]([0-7]([0-8]([0-9])?)?)?)?)?)?)?");
JFormattedTextField ftf =
 new JFormattedTextField(new RegexPatternFormatter(pat));

This uses RegexPatternFormatter from the 2nd edition of the O'Reilly
book "Java Swing":
<http://examples.oreilly.com/jswing2/code/ch20/RegexPatternFormatter.java>

It's not part of the JDK but it's only about 20 lines long and you are
allowed to use it. At least you are probably allowed to use it--see
<http://www.oreilly.com/pub/a/oreilly/ask_tim/2001/codepolicy.html>.