Hello Richard,

I use the LookAndFeelInfo for creating a menu to enable the selection
of all installed LookAndFeels. The strange thing is, that sometimes it
works fine, but sometimes, when I start the application in Windows
style and try to change in another style there occures this execption
in the TableHeader (WindowsTableHeaderUI$XPDefaultRenderer). I think
that the problem is not the way I set the look and feel
(UIManager.setLookAndFeel (info.getClassName () ), it must be
somethings else... It works fine, except the exception in the
TableHeader...

Following the source for the menu:

   UIManager.LookAndFeelInfo[] lnfs = UIManager
       .getInstalledLookAndFeels ();
   for (int i = 0; i < lnfs.length; i++)
   {
     JRadioButtonMenuItem rbmi = new JRadioButtonMenuItem (lnfs[i]
         .getName ());
     lookFeelMenu.add (rbmi);
     rbmi.setSelected (UIManager.getLookAndFeel ().getName ().equals
(
         lnfs[i].getName ()));
     rbmi.putClientProperty ("lnf name", lnfs[i]);
     rbmi.addItemListener (new ItemListener ()
     {
       public void itemStateChanged (ItemEvent ie)
       {
         JRadioButtonMenuItem rbmi2 = (JRadioButtonMenuItem) ie
             .getSource ();

         if (rbmi2.isSelected ())
         {
           UIManager.LookAndFeelInfo info =
(UIManager.LookAndFeelInfo) rbmi2
               .getClientProperty ("lnf name");
           try
           {
             UIManager.setLookAndFeel (info.getClassName ().toString
());
             SwingUtilities.updateComponentTreeUI (mainWin);
           }
           catch (Exception e)
           {
             System.err.println (e.getMessage ());
           }
         }
       }
     });
     lnfGroup.add (rbmi);
   }

Any suggestions for this problem?

Thanks a lot!  Do